Proof: Let
ثبت نشده
چکیده
The PCP theorem states that NP PCP(log n; (log n) c). We build gradually towards its proof. As an intermediate step we show that NP PCP(log n; (log n) c) for some constant c > 1. The presentation here is taken in most parts from 4] (which is heavily based on 2], where NP PCP(log n log log n; log n log log n) was proved. We save a log log n factor in the number of random bits (at a cost of a polylogarithmic factor in the number of query bits) by making the following change to the FGLSS protocol: we use low degree extensions rather than multilinear extensions. These low degree extensions were used in 1]. So as to save myself some rewriting, I kept the original notation of the FGLSS paper. Hence the veriier will be denoted by M, and it has access to an \oracle" O (the PCP witness). The whole PCP system together is referred to as a probabilistic oracle-machine. In this notation, we prove: Theorem 1 Any language L 2 NP is accepted by a probabilistic oracle-machine M such that that uses O(log n) random bits and queries O((log n) c) bit locations, where c > 1 is some universal constant. M takes polynomial time to decide upon the query locations and to write down a list of tests to be made on the replies to the queries. Evaluating these tests takes polylogarithmic time. We now proceed to describe the ingredients of our protocol. 1.1 Polynomials We recall here some simple facts regarding polynomials and multinomials over any ((nite) eld F. Lemma 2 For every set of d + 1 (point,value) pairs f(a i ; b i) : 1 i d + 1g (where a i ; b i 2 F and the a i s are distinct), there is a unique polynomial p(x) of degree d such that p(a i) = b i for every i. L i (x) = j6 =i x ? a j a i ? a j be the polynomial that is 1 at a i and 0 at all a j for j 6 = i. Set p(x) = X b i L i (x): Uniqueness follows the fact that over a eld, every two degree d polynomials either agree on at most d points or agree on all points.
منابع مشابه
Groups with one conjugacy class of non-normal subgroups - a short proof
For a finite group $G$ let $nu(G)$ denote the number of conjugacy classes of non-normal subgroups of $G$. We give a short proof of a theorem of Brandl, which classifies finite groups with $nu(G)=1$.
متن کاملThe Basic Theorem and its Consequences
Let T be a compact Hausdorff topological space and let M denote an n–dimensional subspace of the space C(T ), the space of real–valued continuous functions on T and let the space be equipped with the uniform norm. Zukhovitskii [7] attributes the Basic Theorem to E.Ya.Remez and gives a proof by duality. He also gives a proof due to Shnirel’man, which uses Helly’s Theorem, now the paper obtains a...
متن کاملA SHORT PROOF OF A RESULT OF NAGEL
Let $(R,fm)$ be a Gorenstein local ring and$M,N$ be two finitely generated modules over $R$. Nagel proved that if $M$ and $N$ are inthe same even liaison class, thenone has $H^i_{fm}(M)cong H^i_{fm}(N)$ for all $iIn this paper, we provide a short proof to this result.
متن کاملA NEW PROOF OF THE PERSISTENCE PROPERTY FOR IDEALS IN DEDEKIND RINGS AND PR¨UFER DOMAINS
In this paper, by using elementary tools of commutative algebra,we prove the persistence property for two especial classes of rings. In fact, thispaper has two main sections. In the first main section, we let R be a Dedekindring and I be a proper ideal of R. We prove that if I1, . . . , In are non-zeroproper ideals of R, then Ass1(Ik11 . . . Iknn ) = Ass1(Ik11 ) [ · · · [ Ass1(Iknn )for all k1,...
متن کاملOn Tychonoff's type theorem via grills
Let ${X_{alpha}:alphainLambda}$ be a collection of topological spaces, and $mathcal {G}_{alpha}$ be a grill on $X_{alpha}$ for each $alphainLambda$. We consider Tychonoffrq{}s type Theorem for $X=prod_{alphainLambda}X_{alpha}$ via the above grills and a natural grill on $X$ related to these grills, and present a simple proof to this theorem. This immediately yields the classical theorem...
متن کاملRegularity of second power of edge ideals
Let G be a graph with edge ideal I(G). Benerjee and Nevo proved that for every graph G, the inequality reg(I(G)2)≤reg(I(G))+2 holds. We provide an alternative proof for this result.
متن کامل